sorry i made the force of kinetic friction equal to Fk!
and i made Fnet = -ma in both directions
then i turned a=v/t and velocity in the downwards direction was 1/2 of that in the upward direction!
it doesn't seem like my reasoning makes any sense and so I am getting the wrong answer
Thank you so much that was throwing off my equation completely!
so i now solved that Fn=Fgcosθ
and when i solved for Fk i got -sinθ
my final answer for μ= -tanθ
does that make sense?
alright this is what i got so far!
going up the hill: Fnetx=Fapplied-Ffriction-Fgsinθ
Fnety=Fn-Fgcos
going down the hill: Fnetx=Fapplied-Ffriction+Fgsin
Fnety=Fn-Fgcos
i tried islating for the force of friction but i ended up getting a big...
oh okay i understand that i just don't quite understand what my equations would look like. I'm pretty sure i have to use force calculations but not sure how to put it all together
Hi I'm new to threads I came across a similar question in my homework problems and am still unsure on how to solve it! I unerstand you need to set up two equations for up and down the hill but how do you incorperate the angle into the equations? Any help would be appreciated I'm a little lost!