Recent content by Pepo

I have try it plugging it with h=H-Z in mathematica but the solution is a mess. I really don't know how to get an expression for H(t) from this. :-/

In cylindrical coordinates you have 3 dimensions, r,Ø,z The conversion from cartesian to cylindrical is x=rCosØ y=rSinØ r=sqrt(x^2+y^2) So you equation will be: Outside: r^2*cos^2(Ø)+r^2*sin^2(Ø)+z^2=16 => r^2*(cos^2(Ø)+sin^2(Ø))+z^2=16 ; cos^2(Ø)+sin^2(Ø)=1 is a trigonometric identity then...

Nonlinear 1st order ODE \frac{dH}{dt}=B-A*(H-Z)^{3/2} where: B,A and Z are known values H=f(t); H is function of t I've already solve this ODE numerically using a 4th order RK routine. But my question is, it is possible to get an analytical solution for H(t)?