Recent content by Perdition
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Force exerted to a falling object
getting closer :P thanks I guess it was just an error in rounding the number- Perdition
- Post #6
- Forum: Introductory Physics Homework Help
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Force exerted to a falling object
i assume you substitute s with 0.006 m right. I tried that in that case v^{2}_{f}=v^{2}_{i} + 2 * a * x 0=6.3^{2}+2*a*0.06 0=39.69+0.12a -0.012a=39.69 / (-0.12a) a=330.75 m/s^2 F=m*a F= 12 * 330.75 = 3969 N however the answer should be 4.1 kN- Perdition
- Post #4
- Forum: Introductory Physics Homework Help
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Force exerted to a falling object
Homework Statement A rock with a weight of 120 N free falls from height of 2.00m collides with with Earth and digs 60 mm into it. What is the Earth's average force of resistanceHomework Equations F=m*g => m=F/g m*g*h = 1/2*m*v^2 v=√(2*g*h) The Attempt at a Solution I found the...- Perdition
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- Falling Falling object Force
- Replies: 5
- Forum: Introductory Physics Homework Help
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Velocity and Acceleration within first 10 seconds
English isn't my first language, can you confirm if i understood it correctly please. I use the normal v= s/t formula. I get value of s by placing t=10 to the equation of motion given to me? The value s then I divide by 10...- Perdition
- Post #3
- Forum: Introductory Physics Homework Help
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Velocity and Acceleration within first 10 seconds
Homework Statement Body's linear equation of motion is s= A + B*t + C*t^3 (A= 2.0m, B = 3.0 m/s, C = 0.010 m/s^3) What is the velocity and acceleration of a body on t= 0 s and t = 10 s. Calculate the velocity and accelerations average values within first 10 seconds, starting from start of the...- Perdition
- Thread
- Acceleration Seconds Velocity
- Replies: 3
- Forum: Introductory Physics Homework Help