Recent content by PermaTrashed

Sorry I couldn't find the gamma key, so that all seems correct then? Thanks for all the help!

Word, that makes more sense, so t'=ζ(t-vx/c2) and then I find the angle between y=5t' and x=ζ(x'+vt) then plug in t' and x'=0?

Right, so y'=5.0m/s(t') in the spaceship frame, and then x=ζ(x'+vt)?

in the spaceship frame, y'=5.0t where t=ζ(t'+vx'/c^2)?? Then in the Earth's frame x=ζ(x'+vt), then its just the angle between x and y?

What I don't understand is that from reference of Earth, the tilt of the surface of water won't change, it still will be horizontal, just moving in the diagonal direction. Is this angle (the angle at which it travels diagonally) what I'm looking for?

But it's not asking for the velocity, it's asking for the tilt of the water WRT the horizontal axis in Earth's frame

Wow I do have it wrong then, I totally thought the water rising was due to the gravitational field of Earth, it doesn't say anything about astronauts pouring water into it, thanks a lot!

Homework Statement A relativistic spaceship is moving "horizontally" past Earth at 99% speed of light (c), and the water in the ship's swimming pool rises at 5 m/s. What is the tilt of the water surface with respect to the horizontal, AS OBSERVED FROM EARTH?Homework Equations The Attempt at a...