PeroK's latest activity
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I was watching a video by Brian Cox on the Planck length. At 8 minutes and 31 seconds, he begins to talk about how one, in order to make... -
PeroK replied to the thread Conflicting definitions of linear independence.You have to keep refreshing the page. The vectors should be columns in your matrix. It doesn't work if you make the vectors the rows...
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PeroK replied to the thread Conflicting definitions of linear independence.To be honest, I can't see the point of this alternative condition. Note that it's not a definition of linear dependence. It's a...
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PeroK replied to the thread Conflicting definitions of linear independence.The definition of underdetremined is fewer equations than unknows. Your technique of putting the vectors into a 4x4 matrix is the...
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PeroK reacted to JimWhoKnew's post in the thread Calculating <r> from <x> with no further calculation with
Like.
@PeroK's message in #17 worth repetition: The HA Hamiltonian and the ground state are spherically symmetric, which means they are... -
PeroK replied to the thread On more exercise to burn calories.Typical junk foods have so many calories that it's almost impossible to burn them off in any case. It is easy to consume 5,000 calories...
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PeroK reacted to Mark44's post in the thread I Problem in understanding instantaneous velocity with
Skeptical.
The speedometers on my old bikes are strictly analogue, and as far as I know, aren't damped. -
PeroK reacted to jbriggs444's post in the thread I Problem in understanding instantaneous velocity with Like.
The needle has mass and is damped. Undamped needles bounce. A torque that acts on such a needle will not result in an instantaneous...
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PeroK replied to the thread Calculating <r> from <x> with no further calculation.You've probably struggled with this long enough. Let's assume that ##\langle x \rangle## is +ve; i.e., the expected value of ##x## is...
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PeroK reacted to Mark44's post in the thread Conflicting definitions of linear independence with Like.
That was in reference to your example. If you have 5 vectors in ##\mathbb R^4##, they can't possibly be a linearly independent set. But...
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PeroK reacted to Mark44's post in the thread Conflicting definitions of linear independence with Like.
As already pointed out, but I mention it for emphasis, the coefficients are the scalars that multiply the vectors, not the coordinates...
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PeroK replied to the thread Calculating <r> from <x> with no further calculation.That's one way to look at it.
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PeroK replied to the thread Calculating <r> from <x> with no further calculation.Not really. It's more fundamental than that. You've never answered my question about left and right.
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PeroK replied to the thread Conflicting definitions of linear independence.Those are components of the vector. The coefficients are the scalar multiples of the vectors in a linear combination. In any case...
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PeroK replied to the thread Conflicting definitions of linear independence.There is no 4th coefficient if there are only three vectors.