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Graduate Volterra equation, asymptotic behaviour
OK, but as I see it, both the "exp(-tau/2)"-term and the "1/tau"-term are valid for large x only, i.e. for large "tau" only. And for very large "tau", the latter term is dominant. Hence, as I understand it, this is not an issue meshing togehter a "small x" region and "large x" region. I still... -
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Graduate Volterra equation, asymptotic behaviour
The formula I have derived analytically is value for large x only. The result is (see PDF-file): c(tau) = exp(-tau/2) + exp(i*b*tau)/(Pi*b*tau)This analytical derivation is almost right, but not quite: The "fitting formula" c(tau) = exp(-tau/2) + exp(i*b*tau)/(2*Pi*i*(b-1)*b*tau)is, on... -
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Graduate Volterra equation, asymptotic behaviour
Thank you for your reply! I have expanded the Cosine- and Sine integral for large values of the argument. (Hence, I have not 'taken an approximation around 0', as I understand it). I don't understand what you mean by 'find an expansion close to 0'. What do you mean? -
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Graduate Volterra equation, asymptotic behaviour
Dear all, I want to solve the Volterra integral equation (of 2nd kind). But I only need to solve it analytically for large times "tau", i.e. I only need the asymptotic behaviour as "tau -> infinity". By simple algebra, I obtain an approximative analytical expression in this limit. However... -
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Graduate Inverse Laplace transform for small 's', Taylor expansion
Dear all, This question is close to the post "Laplace transform of a Taylor series expansion" in PhysicsForums.com, dated Jul06-09. This is my problem: Consider the Laplace transform F(s) = 1 / ( s - K(s) ) , where K(s) = -1/2 + i/(2*Pi) * ln[ ( Lambda - (b+i*s) )/( b + i*s...- perr
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- Expansion Inverse Inverse laplace transform Laplace Laplace transform Taylor Taylor expansion Transform
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- Forum: Differential Equations