Recent content by petha1

Thanks for the help. I think I figured out the correct way to answer this question. October 21 is 9 months since the vernal equinox. That means that the LST at noon is 18, leading to the LST at midnight beeing 18+12 = 30 = 6 (mod 24) so the visible RAs are in the range [6-2,6+2] = [4,8]so the...

March 21 - October 21 = 7 months. So the star is only 15m 39,3 seconds behind the sun. This means that the star won't be up when the sun is down. Answer: No, the star will set only 15 minutes after the sun has set. Therefore it won't be on the sky at the specified latitude during dark hours...

I honestly don't understand what you are asking of me. I have banged my head for 6 hours straight on these 3 questions, and I am nowhere near an answer. Are my equations wrong? Are my calculations wrong? I solved two of the questions now. Turns out that R=9400km was the radius from the middle...

I have shown my calculations as far as I have done them, but they are nowhere near the correct answers. E.g. Mars has a mass of 6,39×10^23 Kg, my answer is nowhere near that answer. Am I thinking wrong? Are my calculations wrong?

1. Keplers third law (and the asumption that M1+M2 ~ M1) gives that M_Mars = 4*Pi^2*a^3/(G*T^2) With numerical values inserted Mmars = 4*3.14^2*(9400*1000+3396.97*1000)^3/((6.67*10^-11*(7*60*60+39*60)^2) 2. Phobos needs 7h39 minutes to complete a circle, this gives a speed of...