Recent content by Petrucciowns

Yes, but those conversions don't match up with the variables that I have.

How would I go about converting 59.7 mw/m^2 to lux? I would appreciate any help I can't find an equality.

What do you mean like this? (cl*ml)(TF)+(cg*mg)(TF)= (cg*mg)(TG)+(cl*ml)(TL) then TF/TF = TF= (cg*mg)(TG)+(cl*ml)(TL) / (cl*ml)+(cg*mg)Looks like I got it ehhhh? I really appreciate your help, I hope I can remember this

Ok, I see so cl*ml*TL- cl*ml*TF = cg*mg*TF-cg*mg*TG becomes: cl*ml*TF+cg*mg*TF= cg*mg*TG+cl*ml*TL?

But both sides are filled with variables, don't you have to clear one side to be able to have the side clear for TF?

By doing that I get: TF= cg x mg x TG / Cl x ML x TL- CL x MLOnce again my algebra skills are really lacking so bare with me.

lol.. So I'm probably going to screw up again ,but would the next line be TF = cg x mg x TF - cg x mg x TG / cl x ml x TL - cl x ml ?

Soo... the first line would look more like: cl*ml*TL- cl*ml*TF = cg*mg*TF-cg*mg*TG?

Hmmm, thanks for the help but, I'm still not getting it. Here is what I'm trying so far. Sorry algebra has never been my strong point. :( cl* ml*TL-ml*TF = cg* mg* TF - mg *TG then TF/1= cg * mg* TF-mg*TG / cl *ml*TL-ml ----- I think this is where I screw it up then: TF/TF =...

How would you solve cl *ml *(TL-TF)= cg*mg*(TF-TG) for TF? The text gives it as Tf= cl*ml*TL+cg*mg*Tg / cl*ml+cg*mg If you are wondering the basic equation is for method of mixtures Thank you.

Awesome thanks, I can't believe I didn't realize that. I guess I was just really stressed out.

I see, well how do I find F applied then?

That must be it. The calculation is shown for frictional force is: f= F applied - Mt1*a1Those values are: Mt1= .109 g a1=.332 m/s ^2 and I found F applied by m*g which were: m= .109 kg (the cart and 1 quarter) and g= 9.80 m/s ^2 (acceleration due to gravity)Also it says above in the...

No you don't understand the .333 m/s was the value from the computer software picked up by the motion sensor.

Ok, my experiment consists of a physics cart. It has string tied to it with a paper clip on the end. The paper clips starts out with 1 quarter on it as a weight which is hung over a pulley tightened to the table. A motion sensor sensor is connected to my pc which measures distance on the y...