Recent content by PhysE

Ahh I see now, I was getting charge and current confused, and the average charge on the capacitor would be half of maximum charge, but the current would be the rate of flow of this charge which stays constant (or is for the purpose of finding an average). Thank you very much for your help.

Thank you for your reply. The equations know are C=Q/V, I think that is about the only thing I have covered yet with regards to capacitance. The question is what I have posted above and included no additional details. Current is the rate of flow of charge, I am aware that current decays and...

Hi all, I have been looking at this problem for a while now and can not seem to be able to reach the correct answer, hopefully someone out there can help me! A capacitor of capacitance 180pF is charged to a P.D of 12V and then discharged through a sensitive meter. This sequence of...

Thank you for your reply. However, I think I worded my question incorrectly. I am wondering about lowering the PD of a component, for example using a 10V bulb as opposed to a 12v bulb. If the resistance of the two bulbs are the same the current through the bulb must decrease, why does the P.D...

Thanks for all the replys, they certainly made for some interesting, at least the parts I could get my head around did. I have another question regarding voltage that confuses me, I have tried to use a practical example to explain it, hopefully you can follow my logic and spot any places I have...

Will do! Thanks.

Thank you Inquisitive one. That explanation was definatly very helpfull. However, it seems a little counter intuitive that an increase in the voltage would not increase current. As current is just the amount of charge that flows past a point in an amount of time, doubling the voltage would...

Thank you cwilkins. I think that explanation has eased my mind, for now. It always mentioned in the textbooks P.D was the energy per charge and also the driving force, but it never elaborated and left me stumped with two seemingly conflicting ideas.

Thank you for your answer Claude. I realize what you are saying about using the forums to further my knowledge and will hopefully have the chance to pursue physics further in the future, and by browsing a few threads I have certainly witnessed what you are talking about! However, I feel that I...

Hi all, first post, I hope this is the right place. As I understand, voltage is a measure of the energy given to each coloumb of charge. Therefore, a cell with a higher emf will give more joules of energy to each coloumb of charge. However, voltage is also the driving force behind getting...