Ok, I think this has been helpful. I see two of my errors now.
Would it be correct to say that the lim x->0 of 1/x^3 = DNE?
And I'm still unsure how the absolute value component is affecting the answer for b and d.
a) totally makes sense now, it is basically graph 3.
b) since the limit does not exist as x -> 0, 1/x^2 + 2 would satisfy - because it is absolute value of f(x), 1/x^3 + 2 would also work.
Am I on the right track here?
Thanks again for the guidance.
Thanks all for replying.
Simon, you are right that it can be any function.
I think I am having a very fundamental misunderstanding (still the first week of class, and I haven't taken precalc in 12 years.
I don't understand how the limit as x approaches 2 can be 3, but f(2) = 4
Homework Statement
For each of the four cases below, sketch a graph of a function that satisfies the stated conditions. In each case, the domain of the function should be all real numbers. (professor also mentioned he wants us to write it out in piecemeal function format)
a) lim(x→2) of...