Recent content by Physics08

It's obvious that no one is able to solve this problem because they only ask questions (that lead nowhere) and all the information to the problem has been posted. Thank you all for your help anyway.

I assume the initial y-velocity is zero. No other informtation other than what has been posted is given for the problem Did I use the correct formula?

Yes, I got it right! In the future I will remember to mention that. Also, would you please see my other thread (titled “angle of bullet when fired”) and let me know if I am on the right track for answering the question. FYI, there is no additional information to the problem (titled “angle...

Thank you very much, Silvashadow

OK, how 'bout this? V(y-final) = V(y-initial) + a(y)t V(y-final) = -9.8m/s^2 * 3 V(y-final) = -29.4 m/s then find angle using inverse tangent Angle = tan-1 (-29.4/300) Angle = -5.52 Is this correct?

Homework Statement A bullet traveling horizontally at a speed of 350 m/s hits a board perpendicular to the surface, passes through it, and it emerges on the other side at a speed of 210 m/s. If the board is 4 cm thick, how long does the bullet take to pass through it (in seconds)...

Hi, Could somebody please tell me what formula(s) to use to find the answer to the following problem? A bullet is fired from a gun at 300 m/s. It hits the ground 3s later. At what angle (in degrees) above the horizon was the bullet fired? (Assume no air resistance) Thank you in advance