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Linear Polarizers and Light Intensity
Got it thank you- Physics105kid
- Post #9
- Forum: Introductory Physics Homework Help
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Linear Polarizers and Light Intensity
Okay I think I'm getting it. So would the relationship between them would be: S6=(costheta^2)^6*S0? And if my thinking is correct, S6 should be equivalent to S0? Leaving me with (costheta^2)^6=1?- Physics105kid
- Post #7
- Forum: Introductory Physics Homework Help
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Linear Polarizers and Light Intensity
I just can't seem to put it all together. I've tried countless different values for theta using the S(n+1) = S(n)cos^2 equation. I guess I just don't get how the formulas relate to give me what I'm looking for.- Physics105kid
- Post #5
- Forum: Introductory Physics Homework Help
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Linear Polarizers and Light Intensity
So do I need to use the equation I posted at all? Or is Sout=Sin*f enough to figure out the answer?- Physics105kid
- Post #3
- Forum: Introductory Physics Homework Help
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Linear Polarizers and Light Intensity
Homework Statement Initially unpolarized light is shining on a series of six polarizers in a row. Each polarizer is rotated by the same angle, θ, relative to the previous polarizer. Choose a fraction (anything less than 1) as your final intensity. What is the angle, θ, such that the...- Physics105kid
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- Intensity Light Light intensity Linear
- Replies: 8
- Forum: Introductory Physics Homework Help