Recent content by physics565

I got it. Thank you all for your time.

Well...i have no reason to assume that either the fluid or the pistons are massless.

Perhaps i wasn't clear. No external force is applied to the third piston except the one from the fluid like jbriggs444 said. The question is how one calculates the pressure exerted on the the third piston. Should i add up the pressures that the first two pistons exert on the fluid?

So what happens when the forces are exerted on only two pistons? Will the third piston move?

Assuming that the fluid is incompressible, if any of the pistons move then at least one of them is pushed out and one of them is pushed inwards. But as long as the three pistons exert the same pressure at the same time and they all have the same surface area, shouldn't they all move in the same...

I was actually trying to understand a different problem. The solution to the previous problem would give me a hint. I have a hydraulic press system with three pistons A, B and C. Each piston has a cross sectional area of ##1 m^2##. A force of 10 N is exerted on each of the pistons A and B at...

Thank you all for your replies. The problem is probably wrong. Note that the wording might not be perfect. English is not my mother tongue.

I have come up with two different solutions but i'm not sure which is the correct one. Solution 1 Pressure exerted by John: ##P_1=\frac{F_1}{A_1}=\frac{10}{0.002} pa=5000 pa## Pressure exerted by John's friend: ##P_2=\frac{F_2}{A_2}=\frac{20}{0.002} pa= 10000 pa## Total pressure...