Hi everyone, its been a while since i posted on here but i thought i could do with all your help once again lol.
Im in my final year of my degree now and half way through my final year project which is basically to analyse a tidal generator patent show the basic principles with a practical...
Well I am adding a graph, but I am not actually gona draw it I am just gona say what the person should plot if they wer to draw 1. But if ur using an ldr u should expect to see that as the distance increases, the current drops.
You would need a battery or maybe two. Because initially the photocell would have a high resistance, and you are connecting it to your circuit so it would need an initial amp reading, then you will have to investiate how the light source affects the current. hope that helps :smile:
So anyone...
lol well i think your smart. when it comes to the graph il plot an intensity current graph. what exactly wil the gradient be showing then? and what would the units be? would it be I/eV?
LOl thank you so much you are a genius. Its all clicked into place now. So i will be increasing r by 5cm each time i change the length. So then i wouldn't have to consider calculating the energy of each photon would i. Thanks a million :smile:
I haven't got that far yet, I am still stuck on the distances bit. see i actually know what to do its just this little bit tripping me up, or maybe I am just trying to over complicate things.
Cool thanks, so does that mean that 'r' would be changing? Because I am using a small led so I am think i should change the distance of the light source in groups of 5cm. So i was wondering how this would affect r (radius) in the intensity formula.
O and does anyone know a site where i can get a good infrared light source from. Preferably an IR led, and not just some lamp thank you. Sorry for double posting.
Erm how do you calculate the energy of a single photon when u are using an led? would i just use E=hf (after i have found the...