Recent content by physicsfailure

3.852272sin(45) = 2.72396 3.852272cos(45) = 2.72396 These numbers are vxi and vyi (initial velocities in the x and y direction)? Would I use the original 3.852272m/s to solve for V final in the following formula: Vf^2 = Vi^2 + 2gy?

How do I separate this into vertical and horizontal components? Would it be something along the lines of 3.8sin(45)? (I'm probably completely wrong that was just a guess)

1.5sin(45) = 1.06 (more accurate, used fully accurate number when doing calculations on the calculator) PE = mgh PE = m*-9.8*-1.06 10.3m = 7/10mv^2 (moment of inertia) M's cancel out... 10.3 = 7/10v^2 10.3/ (7/10) 14.84 = v^2 √14.84 = 3.85227m/s = Vf Is this correct? Should it be...

Haruspex: I cannot use energy equations because I am not given the mass of the ball. Thanks for the help but I guess I am just not getting this, lol.

Why is it inaccurate? What should I do if not that? How do I do this?

haruspex: For time, I could manipulate these two formulas: Vyf = vyi + gt and Y = Vyit + 1/2gt^2. My teacher says to use the first formula but you must first solve for Vyf. However, I'm finding it difficult to find a formula for velocity where I don't need Vi of Vf. I guess my question would...

Haruspex: I am not trying to make people "guess" my variables. My teacher is very unclear and I have a very hard time understanding the subject matter when he explains it and I unfortunately had to miss some class time which didn't help either. According to the formula sheet, he has it noted...

Homework Statement In this problem, I'm rolling a ball off a ramp. The ramp is supposed to simulate a roof. The hypotenuse of the ramp is 1.5 meters and the angle is 45 degrees. The distance from the edge of the ramp to the ground is -5.43 meters. That is the information I'm given. From there...