Recent content by physicsfun88

Yes, i thought the length was the 50, but it was the 1.2 from the diagram.

for f=v/lamda I got the 187 Hz. Speed being 112, and with Wavelength being .6.

Magical, that was the issue. It really was just that simple but with the diagram. Thank you!

After playing around with it. By using the aforementioned speed and the equation f=v/2L and using L=1.2. I find that 1.87. which is a few decimals off, but I think I'm close to it. v in that equation being equal to the square root of T/(m/L)

That is my issue, I'm not sure whether 8f is referring to the diagram, or the previously gained data in the problem...

Here is the problem in question. I can't seem to explain it without that picture of the string vibrator. on that worksheet i know that 8d is 4.41 N and 8e is 112 m/s. I know that 8f is 187 Hz but don't understand how to get that answer.

I'm not getting that same answer. T=4.41 m=0.0175 kg and L=50. which comes to 112.25. This is a worksheet from a teacher, I am a tutor, and the teacher for this student teaches wildly away from the book, so I am trying to find the simplest way to do this. His answer sheet says 112 for the...

Homework Statement a 50m length of string with mass 0.0175 kg has waves traveling at 112 m/s. There is a mass attached to the string, 0.45 kg that is creating a 4.41 N tension. What is the frequency of the string vibrator? Homework Equations v=f*λ f= [√T/(m/L)]/2L The Attempt at a...