Recent content by physicsgirl8

you're a genius ;) thanks for helpin ;)

nice...so- final final question...and this is just for me...this car (it's called the nissan leaf) it seems by our calculations tonight - that it's power is approx 58 kilowatts...but nissan advertises it's engine power at 80 kilowatts...can anyone think of a reason why there could be a...

terb...sooooo...576,888.54 divided by 9.9 seconds = 58,271.57 ...but what is the SI unit ...watts ? so 58 kilowatts would be the answer approx ?

thanks terb! one more ?? the next question is "Calculate the average power during the acceleration period of 9.9 seconds" anyone that can give me some tips on this final part of the assignment ?! u guys r great !

this stuff is tough ! They are asking me to find the total work done to get to a speed of 60 mph...wouldn't that be the same as the KE ...in other words - 576,888.54 J ? I'm confuzed ;)

all I know is that according to the work-energy theorem, if one or more external forces act upon a rigid object, causing its kinetic energy to change from Ek1 to Ek2, then the mechanical work (W) done by the net force is equal to the change in kinetic energy. For translational motion, the...

or anyone else for that matter! Thx all ;)

thank you sooooo much pengwuino! yay ! my hero ! lol one more for you ...the next question is "apply the work -energy theorem to find the TOTAL WORK DONE to get to a speed of 60 miles per hour" could you puhleeeeese help me with this one ?

this is a 100 level college course ! it isn't supposed be this hard ! anywayyyy - here is the question need some help- problem - the cars mass is 1604 kg- calculate its KE at 60 miles per hour...so- I converted mph to meters per second and got 60 mph = 26.82 meters per second - so -...