Recent content by PhysicsIdiot

how did you get mgsin"theta"?

is there anyway to prove this mathamatically? like the x component of the medallion?

really? my friend from an ivy league school said the velocity was constant and the acceleration was zero... so .. can anyone else confirm which answer is correct?

This is more of a concept problem that I'm trying to grasp. Verbatim from the book: "A box is moving with a horizontal velocity, v, relative to an inertial frame of reference so that a medallion of mass, m, inside of the box hangs from the roof of the box with an angle, theta, relative to...

does this acceleration affect questions 1 and 3?

Bump, I am still stuck on this.

Anyone?

i guess my drawing was off so i made a nother picture; the acceleration is done at an angle: http://img37.exs.cx/img37/3628/sitb0yi.jpg However, it's constant so would it matter for question #2 (or any of the other questions for that matter)?

wouldnt it be: m1 + m2 (g + Asin"theta")? my friend said he got that.. i don't know "A" being the magnitude of the acceleration this is for question # 2

If you look at the picture, the platform is accelerating at an angle (not straight, otherwise the arrow would be straight) (look at the bottom right) Thanks for all the help :biggrin:

Isn't that the other way around? m2 exerts a force (down) of (m2)g on m1 and m1 exerts the same (up) onto m2? And does m1 exert a force of (m1)g up on m2 or does it exert a force equal to m2's force (i.e. m2 * g) yeah, it's right under m2. Sooo... it's F= ma ; F = f(friction) ; ma = f...

http://img213.exs.cx/img213/852/sita2ju.jpg Look at the link above for reference (sorry, I am not very skilled at paint) It's on a horizontal platform moving with a constant acceleration. Question 1: Calculate the contact forces between objects 1 and 2. My Answer: It's a simple...