Recent content by physicsplease

yes the sum of the squares = 848V I had calculated Vrms to be 849 V also thank you so much for your help and explanations, its greatly appreciated!

oh my math was actually wrong on that V_L= 648.4 V V_R = 546.7 V V_L + V_R = 1200 V as expected but using your equation and squaring each gives 848 V which matches the Vrms. Which are they referring to when they ask if it matches the "source voltage" the Vrms of the peak V?

sorry * that was supposed to be a plus not equals in line 1

z= sqrt( (145ohm^2)=(172 ohm)^2 = 225 ohm given Vrms = Vmax / (sqrt 2) = 1200/ (sqrt2) = 849 Vrms i'm going to assume Irms= Vrms/Z so 849 Vrms/ 225 ohm = 3.77 A back to the original equations gives V_L= IX_L = (3.11 A)(172 ohm) = 534 V V_R=IR = (3.11A)(145 ohm) = 451 V ?

well Z= sqrt ( R^2 + X_L^2) also Z= V/I

Homework Statement A series combination of a 22.0 mH inductor and a 145.0 ohm resistor are connected across the output terminal of an ac generator with peak voltage 1.2 kV. (a) At f= 1250 Hz, what are the voltage amplitudes across the inductor and across the resistor? (b) Do the voltage...