Recent content by pietersandi_w

3x + 4y + 2y = 1 The solutions for x, y, and z is { ( (1/3-4l-2m) | 3l | 2m ) }, where y = l and z = m. I've tried this method, presupposing y = l and m = z, then it came to I. l = (1 - 3x -2m) / 4 II. m = (1 - 3x -4l) / 2 If I try to put in either (I) or (II) to x, it would come...

Hi. Thank you for the reply. Could you help me to find x that would satisfy the inequality?

Log x ((x+3)/(x-1) > Log x x ?? I've managed to find 4 conditions for this inequality: 1. -1 > x > 3 2. x > -3 3. x > 0 4. x ≠ 1 but I'm not sure how to write the solution. Is it " 0 < x & 1 < 0 < 3 " ? Thanks.