Recent content by pikapika1

yes but please refer to my question.. my question is why? why do they have a great acceleration with crouched position and by using the block? Can you explain in terms of Fn? Ff = uFn since friction is the force acting on you in the direction of motion.

5 years ago, I was one-sixth age of my brother. In three years my age doubled will match my brother's age. How old is my age. I tried setting up with 2 variables 1/6(I-5) = B-5 2(I+3) = B+3 and solved for I then i get a fraction. is there any better approach to this?

I know that when the sprinter takes off, the friction acts on you that causes his acceleration, same but opposite force that you put on the ground. But why does he start in a crouched position? Is it because to increase Fn? How would crouching increase the Fn? If one's crouched, the Fn would...

so find F when T = 0? f= m1a a= f/m1 m2gsin30=m2a m2gsin30*m1/(m2) = f f= 14.7N

so find F when T = 0?

yea sorry i realized that my numbers were messed up. Could you help me with the latter numbers that i have given?

the horizontal force is applied on m1 and since m2 = 1kg i simplified it to m2a = a

A box of mass m2 = 1 kg on a frictionless plane inclined at angle θ = 30°. It is connected by a cord of negligible mass to a box of mass m1 = 3 kg on a horizontal frictionless surface. The pulley is frictionless and massless. m1 O ---------------------\...

great explanation :cool: When we are assigning T's at the two cut points, if you don't mind, can you also explain why both the T is upwards as opposed to pointing opposite direction? (one up, one down)

oh ok thx if you were to explain in terms of clouds and circles how would u explain this behavior?

i don't understand how there could be 2 Tensions upward. Why is it 2T= mg? where is the extra T coming from can you explain this in detail i appreciate your help

you lost me at when you said drawing a cloud. Is there any logical way to do it without learning new concepts. so weight down force down 2T up, left and right side of the rope to balance the two downward forces to move in a constant velocity?

ok so the chair would have weight downward and the rope would have force down and T up which doesn't makes sense i'm not understanding this... help me out

A small man is sitting in a bosun chair that dangles from a massless rope, which runs over a massless frictionless pulley and back down to the mans hand. The combined mass of the man and the chair is 95kg. with what force magnitude must the man pull on the rope if he is to rise? Heres a link...