Ah sorry typing error. It meant to be y"=-b - c(y')² the original equation, not just y' by itself. And the signs wrong too, argh, I am silly.
v dv/dy = - b - c v²
dv/dy = - (b + c v²)/v
So then - § v / (b + c v²) dv = § 1 dy
- 1/b § v / (1 + d v²) dv = y + p
d is another constant that I choose...