A chiropractor performs a lumbar spinous pull manipulative procedure. Using instrumentation , she determines 3D coordinates of the axis of rotation of the contacted verebra at t = 15 msec relative to the local axis system as shown. A uniaxial load cell at the spinous process measures a force...
Homework Statement
A chiropractor applies a thrust to the spinous process of T6. The magnitude is 400 N and it is applied 90 degrees to the y-axis. While this occurs the superior disc applies a force to the T6 body of 615 N, 75 degrees to the x-axis. The inferior disc applies a force to...
ok i redid it
i broke everything up in x and y components.
f1= -400 going right to left along x axis
f2= 615 cos 75= 159.17
f3=620cos70=212.05
f4=-32sin60=-27..71 added together = -56.49
y axis
f1=0
f2=-615 sin 75=-594.04
f3= 620sin70=582.609
f4= -32cos 60= -16 added together = -27.43
x2+y2...
i tried switching them everywhere i did
615 cos 75+ -620 cos 70 +- 32 sin 60= 183.96
-615 sin 75+ 620 sin 70 + - 32 cos 60= 718.28
33841.281633841.2816+515930.16 = 549771.4416549771.4416^(1/2) = 741.47 N
400n is going left to right. ( apparently) that is exactly the question that came with the diagram! everyone seems to have 25.6 for angle. I am not sure where they are calculating this from. and 62.8 for resultant.
my friends have come up with 2.90 degrees and 62 or 64 for magnitude and 3rd quadrant of cartersian coordinate system i have no idea why? i was looking for force in N and then respect to x axis.
A chiropractor applies a thrust to the spinous process of T6. The magnitude is 400 N and it is applied 90 degrees to the y-axis. While this occurs the superior disc applies a force to the T6 body of 615 N, 75 degrees to the x-axis. The inferior disc applies a force to the T6 body of 620 N, 70...