Recent content by pinky2468

No, the answer(according to the book) is 800eV

If I do that it changes answer. I got 800 J and the answer is 800eV. If I divide that by 1.6E-19 I get 5E21?

So is KEf= KEi+EPEi-EPEf right? The answer is 800eV and if I do this... KE=0 +(250)(+2)-(-150)(+2) ...I get 800J. So do I need to multiply the +2 charge by 1.6X10-19? If so then that changes the answer, I am missing a step somewhere right?

Here is the problem: Point A is at a potential of +250 V, and Point B is at a potential of -150 V. An alpha particle is a helium nucleus that contains two protons and two neutrons; the neutrons are electrically neutral. An alpha particle starts from rest at A and accelerates toward B. When...

I see what you are saying. Is it 3.4x10^-17?

So if I multiply them by 9.11x10^-31, I get 1.7x10^-17 But, I must be missing something b/c wouldn't the difference be zero? Do I add and subtract 9.11x10^-31 to 1.7x10^-17, the answer doesn't change

Object A gains -1.9x10^13 and Object B loses +1.9x10^13? If that is right, would the next step be to multiply by mass of e-

Ok , so if I use N=q/e I get Na=-1.9x10^13 and Nb= +1.9x10^13? Is that right?

I know this is an easy problem, but I am still confused about how to do it! If anyone can give me some more guidance on this...I can't finish my homework b/c I don't even know how to do the easy problems!

Would the net charge be 0? Then do I take the net charge and divide it by -1.6x10^-19?

It does help, but I am still not sure how to proceed. How do I figure out how many electrons have been transfered? There are no examples in my book and all I know is that q=Ne...N=q/e?

I need some serious help! Unfortunately, my teacher this semester does not think that he should teach is, but that we should just learn it ourselves! So, this is a very simple problem, but since I have no direction, I don't know where to start: Object A is metallic and electrically neutral...

Last question for the semester, but Physics II is right around the corner! This is an easy question but I am not sure how to answer it! A steel ruler is accurate when the temperature is 25 degrees celsius. When the temperature drops to -15 degrees celsisus the ruler no longer reads correctly...

HCl is a pH 2 and NaOH is about pH-13-14 right? So, pH 2 is a buffer solution when HCl is added and not when NaOH is right? The rest I am still lost on!?

I am very stuck on this question and I am hoping someone can help me with this. We did this in lab and mine did not come out right, but I still have to turn it in and my lab teacher said to figure it out! Buffer solutions using a cabbage dye indicator: Which of these is a buffered solution...