i'm asking Clark Magnuson, because he brought up designing circuits, so i assume he has experience building capacitors, and yes the dielectric is relevant to electrolysis, because water in a capacitor acts as a dielectric with coefficient value ~80.4, and I am wondering if there is anything he...
Maybe not in this case there isn't, but in the case of my undergrad project it is relevant. And to my understanding current does not flow between the capacitor plates in pure water situations, which is why people use electrolyte because
Electrolysis of Water: Pauling, Linus (1970) General...
I know the energy on the plates is U = CV^2/2 where U is the energy, C is the capacitance, and V is the voltage.
In this case I'm assuming that the plate configuration creates a parallel plate capacitor
You're saying that some of this energy is heating the water, right? That makes sense. Along...
Nevermind I think you're right that it's 47% efficient
Where does all that energy go I'm wondering?
And btw i think the hydrogen combustion energy output is 286 kJ/mol, so the efficiency would be
0.03 * 286 = 8580 kJ
-> 8580/15163 * 100 = 56.59%
Hmm I think you're right, I thought the hydrogen was being separated from the oxygen for some reason.
Either way though, don't you need oxygen for the combustion reaction i.e. 2 H2(g) + O2(g) ->2 H2O(g) + 475 kJ ?
I could be wrong, but that's what I thought
i saw that too, yeah.
that's like a final step sort of thing after i design the system, and the fundamentals are finalized i'd probably do control tests to compare different electrolytes
no they don't wall start with water, but water covers 70% of the surface of this planet
there's other ways of getting hydrogen, like through gasification, which is when high temperature steam reacts with methane, or something, but other methods of getting hydrogen haven't been introduced to me...
Yeah, I put input/output, and 15163/10602 but i meant the inverse. Thanks.
And in terms of cars, yeah you make a valid point, but for now I'm just looking for the most efficient way to convert electrical energy into hydrogen gas, because there are other uses for them; rocket propulsion being one
So i just watched this guy test a Punch 5.0 HHO generator, which claimed near 100% efficiency
and I used his voltage, current, and time measurements to calculate the energy input. He produced 1 liter of hydrogen gas, which is 0.044643 moles, because 1 mol H2 = 22.4L
The Input energy = V*i*t=...
To clear things up, I know 1 mol of water requires 237kJ of energy to dissociate into hydrogen and oxygen plus 49kJ to overcome the change in entropy of the reaction, and I know you get 237+49=286kJ of energy back from combusting the hydrogen and oxygen back into water.
I'm trying to dissect...