Recent content by Pizall

ok m2 = 150 kg right? I did come up with 150 kg the second time I work it but was not sure. so I worked it a different way and came up with 3 kg, what I did was cancel out m1 on each side, but now I see that I can't do that because I didnot have m1 only but also had m2 so i could not...

so m2 = 3 kg hopfully that is right

so would you work it out like m1v1 - m1v1'/ v2' =m2

Oh ok I think I am with you, the both are 2.50 m/s

v1' is initial velocity which equals 0, and v2' is the the combonation of the boy and the cart velocity which equals 2.50

I first work it like m2v2 = m1v1 but not sure it that was right

I have the equation that starts m1v1 = m1v1' + m2v2'

A 50 kg boy runs at a speed of 10.0 m/s and jumps onto a cart originally at rest. The cart, withe the boy on it, then takes off in the same direction in which the boy was running. If the cart with the boy has a velocity of 2.50 m/s what is the mass of the cart? I need the equation to find the...

so when I plug in the number I come up with a speed greater then What you started with. Started with 20 and after the math its 26 how is this

this is true it chp 4 4.7 Conservation of energy so PE2 should be negative due to gravity so KE1 = KE2 - PE2

so it come up to v2 = 26.34 m/s how is going faster going up the hill then what it started out?

so it should be 1/2mv2 = 1/2mv1 - mgh 1/2v2 = 1/v1 - gh v = square root of v1 - 2gh ? Yes or No?

Hi, new at Physics so go easy. My question is: A roller coaster is traveling on a horizontal track at 20 m/s. What is its speed after climbing a hill 15m high? Ignore friction. any help will be great.