Recent content by polepole

Well that's actually the problem we haven't done many exercises, only a few examples during class which were much easier than the exercises in the book... thanks for the link

btw: thanks for the help

hehe, sorry I saw it already (and found the answer). Could you give me some advice on how to solve integrals fluently?

hmm i see, now I've got integr: du/(1-u)² with u=tanx but what now?

dx/(cosx -sinx)² Homework Equations I changed it to: dx/(1-2sinxcosx) but from there I don't know what to do, i tried partial integration and substitution ... thanks

So you would've used t=sqrt(3X-1) ?

I forgot to multiply with 1/3 from du/3. becomes: 1/9\int(u+7).du/\sqrt{u} = 1/9\intu .du/\sqrt{u} + 7/9 \intdu/\sqrt{u} = 1/9\intu .du/\sqrt{u} + 14/3. \int \sqrt{u} but I've found the solution from there. btw: if you split the integral you can use 7 as an a constant and put it in front...

\int(X + 2)/\sqrt{3X-1} [b] one of my attempts: u=3X-1 , du/3=dX , x = (u+1)/3 1/3\int(u+7).du/\sqrt{u} = 1/3\intu .du/\sqrt{u} + 7/3 \intdu/\sqrt{u} = 1/3\intu .du/\sqrt{u} + 14/3. sqrt{u} = stuck... the answer should be 2/27 . (3X + 20) .\sqrt{3X-1}