Recent content by Poposhka

the force of lift excerted on an airplane is defined as F = Lc * D * v^2 * A where Lc is the lift coefficient, D is the air density, v velocity, and A the lift area of the wing structure. If i use SI units, the Force is expressed in Newtons. What I'm trying to grasp here, is how does this apply...

Ok i think i figured it out, Thanks Al, i gathered that, when i posted that last note, and realized my error.. see what you think of this. It's in C code, but i'll simplify it so that it might make sense... the sequence of operation goes from top to bottom. F = 1 m = 1 d = 0 a =...

aah i think i know what the problem is here ...let me investigate ... :smile:

here's how i got 55 m from my original statement... t= 0.00, d= 0.00, v= 0.00, a= 1.00 t= 1.00, d= 1.00, v= 1.00, a= 1.00 t= 2.00, d= 3.00, v= 2.00, a= 1.00 t= 3.00, d= 6.00, v= 3.00, a= 1.00 t= 4.00, d= 10.00, v= 4.00, a= 1.00 t= 5.00, d= 15.00, v= 5.00, a= 1.00 t= 6.00, d= 21.00, v= 6.00, a=...

Actually i think i have a fundamental flaw in my understanding here... let's backtrack for a second... Since 1 Newton is the force required to accelerate a mass of 1 kg at a rate of 1 m/s/s (or m/s^2). Does that mean that a increases by 1 each second? So at t=0, a=0, t=1 a=1, t=2 a=2, t=3...

I'm not sure if this is wrong, but here's what i went off of. http://www.google.com/search?q=1+m%2Fs%5E2+in+m%2Fms%5E2&sourceid=mozilla-search&start=0&start=0&ie=utf-8&oe=utf-8&client=firefox-a&rls=org.mozilla:en-US:official

hey all, I'm pretty ignorant when it comes to physics.. so i have a question for you physics braniacs. If 1 N is 1 kg m / s^2, meaning the force required to accelerate a 1 kg object at 1 m/s^2, then how much does 1 N accelerate a 1 kg object over 1 millisecond? I googled for 1 m/s^2 in m/ms^2...