I am starting to think that taking the rate of deceleration into account and all that, is complicating things unnecessarily and that the F=ma approach might be valid and a close enough approximation for my application.
The fact that I am only interested in Fmax, which occurs at V0, which in...
I most definitely believe that either speed or acceleration (I can’t wrap my head around which one of them ATM) will change as a decaying exponential and I believe that the initial vector of that is key to finding the force I am looking for.
Yes, I am familiar with derivatives, integrals and...
On the contrary. I want to find the correct math to get away from intuition and assumptions. Since I am no physicist or physics student, but just a layman, I am turning to you guys for help with this.
I don't see how that applies here. If the acceleration would be constant (and the velocity...
a. a = F/(M+m)?
b. a = F/(M+m)?
c. m * a? Rightward?
Is this correct?
Let's modify this example to get closer to my initial question:
Instead of a sitting on frictionless table, the blocks are now floating (as in, being buoyant) in a fluid. Instead of a massless rope, the blocks are now...
I tried making sense of the information here in the hopes that it would help me, but I couldn't wrap my head around it: https://physics.stackexchange.com/questions/72503/how-do-i-calculate-the-distance-a-ship-will-take-to-stop
I would actually prefer to simplify further. The box is rigid and unifrom (no space or contents inside), there is no friction whatsoever and also, assume that the rope is an ideal rope which is already taut and has zero elasticity. It could just as will be a rigid connection between the box and...
OK, I’ll buy that. Having thought about this some more, I am wondering about the inertia of the cargo. Could it be like this;
We assume that the cargo is standing on a frictionless surface. For the rope to become taut, the drag force on the ship when it stops, must be greater than the inertial...
Well, if it is a vessel with high drag (say a barge, rather than a kayak), then when the engine stops, there will usually be an initial jerk (that sends the cargo flying), after which the deceleration smooths out, right?
I guess that's what I am struggling with here. I can't figure out how to...
A ship is traveling at constant speed, i.e. the engine exerts a force equal to the drag force acting on the ship (right?). A cargo box is standing on the deck of the ship and is secured with a rope to the mast (see pic). When the ship kills the engine, the drag will create a sudden change in...