Recent content by Precal_Chris

oh yeah she said this last six weeks we are going to be doing a lot of calc stuff

is this for like mostly college people or something?

thats what i did at first... and i got the -x^3+4x^2-5 to go into (x+1)(-x^2 +5x -5)/(x+1) and so the (x+1) canceled... but when i told everyone that i got -x^2 +5x -5 for my answer they said that there was no x+1 in the numerator and i had to go through the other equation... and i just...

yeah at my high school they only have precal, cal AB, cal BC and then stats and stuff but since i only have 2 more years of math left at high school this year I am taking precal junior year I am taking ap stats and senior year I am taking discrete math.. (easy math class but teaches you how...

wow and you guys knew how to do this all along... thats crazy how do you guys know all of that?

oh...lol our teacher said there was a way easier way to do this but she wouldn't tell us...

who's OP?

ok then plug in -1 for all the x's which would be.. -3(-1)^2 +8(-1) -3-8 -11?

oh dang that's where i went wrong last time i put h as -1 ...-.- im getting x and h confused... so when h is taken out of the denominator i should have... -3x(^2) -3xh -h(^2) +8x +4h correct? then placing 0's in for h should make it... -3x(^2)- 3x(0)-(0)(^2) +8x + 4(0)... leaving...

ok so i did the whole -(x+h)^3 and the 4(x+h)^2 and the +x^3-4x^2 and when i put them all together i got this: (-3x(^2)h) -(3xh(^2)) -h(^3) +8xh +4h(^2) all over H this is after i canceled out the two x^3 and the two 4x^2's

crap... ok can you tell me really quick what you got so i can try it until i get it right? ive been on the computer for over 2 hours now..

alright i tried it the whole way through using that and i ended up getting (-3x^2)+ 11x -5

ok well atleast i got the other 2 right ill just try my best on this one because i don't seem to be getting newhere with it..

so: -(x+h)^3 + 4(x+h)^2 - (-x^3+4x^2)/h ? wouldnt that get me -[(x+h)(x+h)(x+h)] -[(x^2 + 2xh + h^2)(x+h)] -[(x^3 + 3x^2h + 3xh^2 +h^3)] (-x^3)-(3x^2h)-(3xh^2)-(h^3) right?

ok so its not 3 its 5... that changes everything... -x^3 +4x^2-5/(x+1) then i can factor out an x+1 which the top and bottom x+1's cancel leaving you with -x^2+5x-5... is this right so far? so i can go ahead and plug in for the x's?