Recent content by Preptopro

Yes correct .92m/s is the speed when the wooden block reaches the pulley. The .2kg mass is also falling down at that time, do I need to calculate the the speed at which it falls? and if so how? How can I correct this then? I do not really have much prior experience with rotational kinematics...

I apologize, what I meant was that the pulled is hooked on the edge of a table and the wooden block is .8meters away from the edge of the table where the pulley is positioned, the wooden block is initially .8meters from the pulley and the .2kg mass is dropped from the table height or .76meters...

Homework Statement So I have a horizontal pulley positioned at the edge of table with a mass of .2kg hanging down from a height of .76meters, the other end of the string is attached to a wooden block of mass .25kg that when the .2kg weight is dropped the wooden block is pulled towards the...