Recent content by Prince1281
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Wheatstone bridge problem unable to understand
Hey I was just thinking about the Rt expression. The general formula for Rt is R0*(1+a* ΔT) but you used Rt = only aΔT+R0. So did you just change the formula just like that because shouldn't it be R0+ R0*a*ΔT? Can you please confirm this.- Prince1281
- Post #26
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
Yeah its 156 nf.- Prince1281
- Post #18
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
Yes we can combine the capacitors in parallel and get a total capacitance. So is the total capacitance to be used with the total resistance in the relevant equation that I uploaded for this problem in order to get the charging time. Please confirm. Thanks- Prince1281
- Post #16
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
No its fine. I just don't understand how can I use only c2 when both the capacitors are in parallel. Just because they share same voltage does it mean I can ignore c1?- Prince1281
- Post #13
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
Oh yeah man sorry you're right I suck at simplifying...if I ignore r3 I will have capacitors in parallel. But what about resistors will they be in parallel too? And also how does having same voltage help...- Prince1281
- Post #11
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
Well capacitors got charge common when in parallel...Not sure how that helps. Explain please- Prince1281
- Post #9
- Forum: Introductory Physics Homework Help
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Wheatstone bridge problem unable to understand
Yes sorry you are right. Thanks a lot. can you also check out this forum https://www.physicsforums.com/threads/capacitor-charging-and-discharging.780167/#post-4903875 I can't get the understanding to this as well. Thanks- Prince1281
- Post #25
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
But it asks only for C2 so shouldn't C1 be ignored somehow?- Prince1281
- Post #7
- Forum: Introductory Physics Homework Help
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Wheatstone bridge problem unable to understand
You told to keep the 10 outside as it will multiply so it will be 600 000/(T+40000)^2, correct?- Prince1281
- Post #23
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
So if its connected to junction a, we can ignore R3 right? can we ignore anything else for the charging part- Prince1281
- Post #5
- Forum: Introductory Physics Homework Help
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Wheatstone bridge problem unable to understand
so dv/dT = 60 000/(T+40000)^2 and now do I put the two different T values in? As in should I get two dv/dT values? Because I have 2 different temperatures to use- Prince1281
- Post #21
- Forum: Introductory Physics Homework Help
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Wheatstone bridge problem unable to understand
Okay at the denominator I had v^2 which is (0.005T+200)^2 which gives me a quadratic equation 2.5*10^-5 T^2 + 2T +40000 so dv/dT = 15/(2.5*10^-5 T^2 + 2T +40000) Is that correct?- Prince1281
- Post #19
- Forum: Introductory Physics Homework Help
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Capacitor charging and discharging
I have no idea sir. This is exactly the information I have. I think its supposed to be some general case. I have weak understanding of this whole circuit concept. Is the total resistance of the circuit R3+R2 then parallel with R1 or is it R1+R2+R3?- Prince1281
- Post #3
- Forum: Introductory Physics Homework Help
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Wheatstone bridge problem unable to understand
I multiplyed with 5 to make it one fraction and then I took u and v. If I differentiate 5 and then take u and v won't it be some sort of double differentiation? If I take u as 0.05T + 1000 then I get dv/dT = 5.05-2.5*10^-4T/(0.005T+200) Is this Dv/dT correct or the previous one?- Prince1281
- Post #17
- Forum: Introductory Physics Homework Help