Recent content by Prince1281

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    Wheatstone bridge problem unable to understand

    Hey I was just thinking about the Rt expression. The general formula for Rt is R0*(1+a* ΔT) but you used Rt = only aΔT+R0. So did you just change the formula just like that because shouldn't it be R0+ R0*a*ΔT? Can you please confirm this.
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    Capacitor charging and discharging

    Yes we can combine the capacitors in parallel and get a total capacitance. So is the total capacitance to be used with the total resistance in the relevant equation that I uploaded for this problem in order to get the charging time. Please confirm. Thanks
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    Capacitor charging and discharging

    No its fine. I just don't understand how can I use only c2 when both the capacitors are in parallel. Just because they share same voltage does it mean I can ignore c1?
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    Capacitor charging and discharging

    Oh yeah man sorry you're right I suck at simplifying...if I ignore r3 I will have capacitors in parallel. But what about resistors will they be in parallel too? And also how does having same voltage help...
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    Capacitor charging and discharging

    Well capacitors got charge common when in parallel...Not sure how that helps. Explain please
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    Wheatstone bridge problem unable to understand

    Yes sorry you are right. Thanks alot. can you also check out this forum https://www.physicsforums.com/threads/capacitor-charging-and-discharging.780167/#post-4903875 I can't get the understanding to this as well. Thanks
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    Capacitor charging and discharging

    But it asks only for C2 so shouldn't C1 be ignored somehow?
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    Wheatstone bridge problem unable to understand

    You told to keep the 10 outside as it will multiply so it will be 600 000/(T+40000)^2, correct?
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    Capacitor charging and discharging

    So if its connected to junction a, we can ignore R3 right? can we ignore anything else for the charging part
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    Wheatstone bridge problem unable to understand

    so dv/dT = 60 000/(T+40000)^2 and now do I put the two different T values in? As in should I get two dv/dT values? Because I have 2 different temperatures to use
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    Wheatstone bridge problem unable to understand

    Okay at the denominator I had v^2 which is (0.005T+200)^2 which gives me a quadratic equation 2.5*10^-5 T^2 + 2T +40000 so dv/dT = 15/(2.5*10^-5 T^2 + 2T +40000) Is that correct?
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    Capacitor charging and discharging

    I have no idea sir. This is exactly the information I have. I think its supposed to be some general case. I have weak understanding of this whole circuit concept. Is the total resistance of the circuit R3+R2 then parallel with R1 or is it R1+R2+R3?
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    Wheatstone bridge problem unable to understand

    I multiplyed with 5 to make it one fraction and then I took u and v. If I differentiate 5 and then take u and v won't it be some sort of double differentiation? If I take u as 0.05T + 1000 then I get dv/dT = 5.05-2.5*10^-4T/(0.005T+200) Is this Dv/dT correct or the previous one?
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