Recent content by psandadi

ok. thank you

I feel like this would be the answer. I, initially drew an imaginiary vertical axis through c and seeing that the network is symmetrical, b and d would have the same voltages. So, I joined b and d to a point x and then added the conductance because they are parallel. By looking at the second...

Can I use the fact that in a complete graph K_n, the effective conductance between any two vertices is (n-1)c/2 where n is the number of vertices and c is the conductance of each edge

I am actually a math guy. This question i came across was talking about the probability of reaching z before a starting from a and the formula is C_{eff}(a,z)/C(a) where C(a) is the sum of all the conductance that are neighboring to a.

Yes, I forgot to mention. I understand that all the vertex except a and z are symmetrical. I do not know where to go after that