Recent content by psstudent

Thanks for the reply, but i figured it out. I got the vertical and horizontal components use Pythagorean theorem and then SOH to find the answer

Homework Statement I have this question to solve for homework : " An object of mass 10 kg is whirled around a horizontal circle of radius 4m" If the uniform speed of the object is 5m/s Calculate a) tension in string b) angle of inclination of string to the vertical.Homework EquationsThe Attempt...

Very true, it seems very poorly worded. Thank you for your help.

Hey haruspex , i checked the question again and it does indeed say " the maximum inclination of the string" so what would recommend me doing? Put it as zero? Put it as "unanswerable" or "redundant"? Thanks !

Ah ok, I got it , I found the angle to be 36.9 so that's my max inclination after teh object hits. But for part a) which asks for the max inclination before collision, wouldn't it just be 0 ? Because it didnt move?

Ok so I worked out the max height as 0.2 m. But I am having trouble properly constructing the triangle to find the angle.

after discussion with someone, i realize the part about friction I ahd was completely off because the object isn't touching. So i can use conservation of momentum to fin dthe momentum of the pendulum after impact, and then us energy =mgh to solve for the max height and use sohcahtoa to find the...

Mentor's note: this was originally posted in a non-homework forum, so it doesn't have the homework template. ------------------------------------Hey guys hoping you guys could help me with this A object (20g) moving horizontally at 100m/s embeds itself in the middle of a block of some wood...

Just want to say thanks to everybody , and a little update: I finally did get the correct answer. Thank you!

thanks, Mfb, yes you're right there was a error I believe it was 1.927 % not .019%.

Just want to preface this by saying thanks to everyone who has helped so far. The homework is due tomorrow and even though I feel like I am close, I don't think ill get the correct answer. I tried two last rolls of the dice and this is what I came up with:(please tell me if any of the values I...

So I used the standard density. That would give me 1000 kg/m^3 X 10 m/s^2 X .185 m. which equals 1850 pa. Isnt that rather large though? Thanks for your reply these answers really help, seeing as the formula in the question seems to have been a typo in the textbook. Also mfb said you use the...

Ok thanks, now I understand you formula, but I am still caught up on the δq as the numerator, what would I put as the value for δq? would I just put "1" or what because i don't have a value for n and the only way i would be able to get a value is to find pressure and then solve the formula...

Mfb, wouldn't Chestermillers approach require me to also find the pressure? So i find the percentage error of each given quantity in the question and then what? Thanks Mfb for the reply.

Hi gneil thanks for your response. I looked up the equation you said pay attention to the exponents , I see that it is 4 instead of 2? Is that what you wanted me to discover, so is the equation given in the question essentially wrong? I realize, what you are saying about the pascal*seconds, so I...