I have this same homework question (but my Ki is .21MeV). Can someone explain it to me in detail? I'm trying to make sure I understand why it's done this way.
I got someone else to look at it and I was apparently distributing the 2/a incorrectly and some other errors.
I got it all worked out and my answer was
(-x^2/a)*cos(ax)+((2x)/a^2)*sin(ax)+(2/a^3)*cos(ax)
Thanks for all of your help! :)
Thanks for noticing that, I think signs are my number one weakness. I tend to look over stuff like that.
I fixed the sign but I don't know if once again I missed something or I'm entering it into the answer box incorrectly.
I've attached a screenshot.
Thanks
[SOLVED] Integral of x^2*sin(ax)dx
So, I'm a newb at Integration, especially by parts.
This is what I have
\int x^{2}sin(ax)dx
I set:
u=x^{2} and dv=sin(ax)dx
so I got:
du=2xdx and v=-cos(ax)/a
So then I put everything together
u*v-...