Recent content by psychochef

I figured it out, so I guess if anybody was wondering I'll just sum up what I did. Since the way the car moves is because friction with the ground, on the free body diagram, the net force in the x direction is the Ffr (car trying to accelerate) - Fgx (gravity in x direction on the tilted axis)...

I got it! T-Ffr = ma I solved for T, got 105N, that seems much better than 2.1 or 80N. Thanks a bunch!

The car is attempting to move up the slope, but the angle is such that all the forces cancel out and the car cannot move/accelerate up the slope. I'll double check and see if the mass was given to me somewhere, but I don't recall it being there. I did end up cancelling the mass out of all my...

Homework Statement Given the max acceleration of a car, 7.6m/s2, calculate the angle of the slope where the cars wheels will spin out. (Fnet=0). Homework Equations Fnet=ma Ffr=μFn The Attempt at a Solution Since I'm not given μ or anything, I think I'll have to figure that...

Awesome! It's good to know that I'm on the right track. So assuming I need to consider the force of Friction on the 2nd box (21kg), here's the calculations I get. Fnet = Fa-Ffr-T = ma solve for T: T= Fa-Ffr-ma Now should I use 185N as my Fa? I know that on the first box the applied...

Homework Statement Two boxes are connected by a massless string. The first box's mass is 16kg and second box's mass is 21kg. You pull with a total force of 185N on the 16kg box. The coefficient of friction is 0.5. Calculate the tension in the string between the two boxes. Homework...