Recent content by Punjabi.Sher

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    How High to Drop a 1kg Mass to Gently Touch an Egg with a Spring?

    I have a similar lab practicum. Basically there is a certain mass on a spring and we need to find the height it must be dropped from. I don't know what heights I should use. I also don't understand how to find the spring constant. Can someone please help me? EDIT: I have not posted any work...
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    What is the average kinetic energy per atom of He in a gas mixture at 448 K?

    Ok there's part 2 to this question. It looks so similar to this, but the same method doesn't give me the right answer. Part 2: What is the average kinetic energy per molecule of Ne? Part 3: What is the average total kinetic energy of He? Answer in units of J.
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    What is the average kinetic energy per atom of He in a gas mixture at 448 K?

    wow, it was just a matter of typing it in correctly. I can't believe this, because I am doing these online, so I didn't know how to type in very small values like with exponents.
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    What is the average kinetic energy per atom of He in a gas mixture at 448 K?

    A gas contains a mixture of He and Ne. The gas is at a temperature of 448 K, with 0.85 mole of He and 2 mole of Ne. Avogadro’s number is 6.02 × 1023 mol−1, and Boltzmann’s constant is 1.38×10−23 J/K. What is the average kinetic energy per molecule of He? Answer in units of J. 2...
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    How Many Helium Atoms Fill a 24 cm Balloon at 76°C and 0.789 atm?

    V = 7238.23 cm^3 x (0.001 L / 1 cm^3) = 7.24 L 0.789 atm (7.24 L) = n (0.082 L·atm·K−1·mol−1) (349.15 K) n = 0.1995 mol x (6.022e23 / 1 mol) = 1.20e23 atoms Still this is not the right answer I think.
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    How Many Helium Atoms Fill a 24 cm Balloon at 76°C and 0.789 atm?

    pv = nrt 0.789 atm (4/3*3.14*12^3) = n (0.082)(349.15 K) n = 199.47 moles = 1.20e26 atoms
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    How Many Helium Atoms Fill a 24 cm Balloon at 76°C and 0.789 atm?

    I tried this problem a lot of times, but just didnt get the answer. The molecular mass of helium is 4 g/mol, the Boltzmann’s constant is 1.38066 × 10−23 J/K, the universal gas constant is 8.31451 J/K · mol, and Avogadro’s number is 6.02214 × 1023 1/mol. Given: 1 atm = 101300 Pa. How...
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