Recent content by qm14

I have finally realized the flaw in my reasoning. I was not taking the negative values into account, presuming that the summation would blow up at - infinity. I really appreciate your input, thanks! .

I am failing to link together how ##\gamma (1/4)^{|n|}= 1 ## Intermediate values of above equation ~ (0.333) for the first few terms.. to meet the unity condition ##(1/4)^{|n|}## must be equivalent to (5/3) since constant is 3/5. What am I overlooking...

Anyone...

I have calculated |a_n|^2 above, I have split summation into two parts.. \sum_{-\infty}^{0} (1/4)^{|n|} = (1/4)^{-\infty} + (1/4)^{0} = (\infty) + 1 Similarly for the range (0,\infty) .

Hi, Yes, I have been asked to find the total probability of a particle in a negative energy state, so how is this answer any different than the previous one. Both summations add up to 1 i.e (-infty,0) and (0,infty).. I thought negative values of N would be discarded due to the^ |N| power, or...

Homework Statement State vector : | \psi \rangle = \sum_{n = - \infty}^\infty a_n| \psi \rangle where a_n= i\sqrt\frac{3}{5}{\frac{i}{4}}^{|n|/2}e^{-in\pi/2} Find the probability of the particle in Nth state. What is the total probability of the particle in 'N' negative state. Homework...