Recent content by qq194

so that's the last question, how can I determine cs from this function equation between f and v now?because $$ y=kx^n $$ that describes only f and V in the diagram, can I determine cs with the help of these straight lines?

thanks for your help!

thank you so much for your really great support!

now it works, thank you , with me the graph looked like a straight line, only my associated function equation y=mx+b was not as perfect as yours. Many thanks, what program did you use?

V= 0,000295m^3 f=172Hz V= 0,000245m^3. f=188Hz V=0,000195m^3 f=211Hz V= 0,000145m^3 f=245Hz V=0,000095m^3 f= 303 Hz V=0,000045m^3 f= 440Hz

There are different volume bet and accordingly different frequencies. I have recorded 7 values, so now I have 7 volume values and their corresponding frequency. @Chestermiller gave me a nice Ln equation, I put in his equation the values, you can see the linear relationship. Do I have to plot the...

I have entered the normal V and f values in the diagram, does the slope have to be -1/2 when running a regression leanest through the points as in your equation. And do I have to adjust the values through the equation when I enter them

I have tried to show the derivation of your equation, can you help me if there is an error in the derivation?or do you have a better derivation how you come to the equation? Because I like your equation very much and I would like to try to understand the derivation $$ f = \frac{{cs}}{{2\pi}}...

Thank you very much! I tried their equation and it worked! The graph looks good too. What do you call the x and y axis? And can you also use the logarithms to form a linear relationship between a function of frequency f and a function of volume V?or is the equation you gave me already the linear...

Okay that means okay thanks, but the rearranged equation that describes the linear relationship between a function of frequency f and a function of volume is f² and 1/V?because I have to rearrange the equation to get this result

or is this one better: $$ f^2 = \left(\frac{c_s}{2\pi}\right)^2 \cdot \frac{A}{VL} $$ $$ \ln(f^2) = 2\ln\left(\frac{c_s}{2\pi}\right) + \ln\left(\frac{A}{VL}\right) $$ $$ \ln\left(\frac{1}{V}\right) = \ln(f^2) - 2\ln\left(\frac{c_s}{2\pi}\right) - \ln\left(\frac{A}{L}\right) $$ $$ y =...

$$ f = \frac{c_s}{2\pi} \cdot \sqrt{\frac{A}{VL}} $$ $$ f^2 = \left(\frac{c_s}{2\pi}\right)^2 \cdot \frac{A}{VL} $$ $$ \frac{1}{V} = \frac{2\pi f^2 \cdot L}{A \cdot c_s^2} $$ $$ \ln\left(\frac{1}{V}\right) = \ln\left(2\pi f^2 \cdot L\right) - \ln\left(A \cdot c_s^2\right) $$

cs = speed of sound L= length= const. A= area = const. V= volume = changes

i will show you my steps: \begin{align*} f &= \frac{c_s}{2\pi} \cdot \sqrt{\frac{A}{VL}} \\ f^2 &= \left(\frac{c_s}{2\pi}\right)^2 \cdot \frac{A}{VL} \\ f^2 \cdot \frac{VL}{A} &= \left(\frac{c_s}{2\pi}\right)^2 \\ f^2 \cdot \frac{L}{A} &= \frac{1}{V} \cdot \left(\frac{c_s}{2\pi}\right)^2 \\...

the problem that I have is to get the function as I have described into a linear relationship between a function of frequency f and a function of volume V