Recent content by quantum_flame

  1. Q

    Trace(matrix) = 0 and the dimension of subspace

    You said > Isn't dim Tr [M_n (F)] = 0 since Tr [M_n (F)] = 0? No, dim Tr [M_n (F)] = 1 since Tr [M_n (F)] = F You have confused M_n (F) (all nxn matrices over F) with its subset of trace zero matrices. And a (non degenerate) field over itself obviously has dimension 1 because it's spanned by...
Back
Top