Recent content by Quazswed

Seems like I was too pessimistic then :) Thank you very, very much for your help

2y1v1 is = 166011471 m/s, I think it's correct now so 2y1v1 = 166011471 m/s = k y2= 1 / sqr(1-(v2/c)2) v2 / sqr(1-(v2/c)2) = k v2^2 = k^2 - k^2(v2/c)^2 (k^2/c^2 +1)v2 = k^2 v2 = sqr( k^2 / (k^2/c^2 +1)) which is 145254607 m/s, it's so close to 150000000 m/s Is this an error caused by...

uops, I'm sorry, i meant E7 anyway I used 8 E7 in the equations Also, edited in the first post, thanks for pointing that out

Homework Statement A particle traveling at 8 E7 m/s is accelerated so that its momentum doubles. What is the final velocity of the particle?Homework Equations p=ym0v y= 1 / sqr(1-(v/c)^2) p2= 2(p1) Where p2 is the final momentum and p1 the initial The Attempt at a Solution For the initial...