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oh... ok. but that means that its value is aproximately 6.6e-11?

so the \pm sign means that you don't know if its 6.7 - 0.0001 or +0.0001? why don't we know that? is it because of the limits of the measurements of the physicists? and twhat are the m kg and s for?

no i understand everything now I made that equation at first aswel, but after what you said i had doubts if it was correct. thank you very much.

so i can't calculate it's speed after 1/30th of a second and then using that as a base calculate its speed after 2/30th of a second etc?

yes, thank you. but my uncle told me that gravitational acceleration on Earth is 9.8m/s(2). and that it means that the first second it will move 9.8m/s(in vacuum and in the second second ca 100m/s this is not true right?

because it's value isn't just a plain number. i don't know what all those signs do there:\pm, m, kg, s, N and cm. if its a constant why are they there? and how do u get 6.67(-11) out of it? aren't you ignoring the 0.001 and the other things?

G is the gravitational constant. it's approximate value is: G = (6.67428\pm0.0010)*10(power -11) m(power 3) kg(power-1) s(power-2) = (6.67428\pm0.0010)*10(power -11) N m(power 2) kg(power-2) = (6.67428\pm0.0010)*10(power -8) cm(power 3) g(power-1) s(power-2) now what is this? is this even an...

but i don't know what "at" is. t is tiem and a is acceleration ok. but a is m/s*s and t is seconds, right? so that would mean: ms/s*s*s and i don't know what that is, so I am probally doing it wrong, what is it?

ah thank you, i guess i was looking in the wrong direction. so to calculate it i guess i would have to use this formula? uf(small f) = ui(small i) + at is this true? because i don't really know how to calculate it. i need to have a list of its speed every 1/30th of a second so like...

the law: a1 = G(m2/r*r) to calculate acceleration with gravity, gives the m/s*s. (i don't know how to type the square sign) but how can u calculate how many m/s an object gains in a certain time?