Recent content by R2311

Right. So the sum of forces must be: pA - F - p0A = 0 To keep the piston in equilibrium, the forces of F + air pressure must equalize the pressure from the oxygen gas. F = pA - p0A = (p-p0)A p0 = 101kPA, area of the piston is equal to that of a circle: A = pi*r^2 Therefore: F = (145-101)kPa...

I'll use the equation of state to find the new volume: (p1v1)/T1 = (p2V2)/T2 Temperature remains the same in this instance so T1 = T2 Which leaves us with: p1V1 = p2V2 I wish to find the new volume V2, so V2 = (p1V1)/p2 = ((145kPa * (pi*(0.080m)^2*0.600m))/101 kPa = 0.0174m^3 Now using...

Aaaah, simple mistake, my bad! :approve:

Yeah, and I also think the degrees must be in Kelvin, which gives 273 + 40 = 313K If the volume must be in m^3 we get 0.04823 m^3, but I don't understand what you mean by A being incorrect. It's a cylindrical piston, so the area of a circle is pi*r^2, and times the height h = 60 gives us the...

a) p = F/A F = pA = 145kPa(60*16)cm = 139200N b) pV = NkT V = pi*r^2*h = 48230 cm^3 N = pV/kT => N = (145kPa*48230cm^3) / (1.38*10^-23J/K * 40) = 1.266*10^28 I think those are right but I'm confused by the last two.

A cylinder containing oxygen gas O2 has a piston that can move unfazed by friction. The piston has a diameter of d = 16cm. The oxygen gas has a temp of 40,0 degrees Celsius and a pressure of 145kPa. The pressure outside the cylinder is 101kPa. The piston is held in a stationary position s =...