Recent content by radtad

How do you evaluate this integral: integral(1/(x^2-6x+8) i don't kno how to subsitute on this or anything. I am completely stuck

At 3 PM a ship which is sailing due north at 12 knots(nautical miles/hour) is 5 miles west of a westbound ship which is making 16 knots. a) At what rate is the distance between the ships changing at 3 PM is it just simply pythagorean theorem of the rates of both ships? i got the answer as...

thanks i think i got it 3.07 N sound about right

Two charges, q1 and q2, are held a fixed distance d apart. a. Find the strength of the electric force that acts on q1. Assume that q1=q2=21.3 micro COulombs and d=1.52 m. b. A third charge q3=21.3 micro COulombs is brought in and placed as shown. Find the stregnth of the electric force on q1...

yea i realized that too thanks

choices are a. 12.566 b. 14.661 c. 16.755 d 67.021 e 134.041 i keep ending up with choice d but the answer key says its choice c

yea according to the answer key its wrong

The base od a solid is a region in the 1st quadrant bounded by the x-axis, y-axis and the line x+2y=8. If cross sections of the solidperpendicular to the x-axis are semicircles, what is the volume of the solid? How come the answer isn't just the intgegral from 0-8 of 1/2pi(4-x/2)^2

thanks forgot the C and yea choice c was a typo it should be e^kt +3

We have a set of problems for hw. I am stuck on 1 where I know the answer but can't seem to get it. If dy/dt=ky and k is a nonzero constant then y could be a. 2e^kty b. 2e^kt c. e^kt d. kty+5 e. 1/2ky^2 +1/2 I know the answer is b but i can't get that answer Here is my work...

i think I am going to go with amax=g but ill let u guys know what it turns out to be when i get the homework back monday

yea i think we need a 3rd party bc one of my friends in my class is telling me its just g and that I am thinking about it too much so i don't know

Fnet=ma Fs-Fg=(m+M)amax amax=(kx-(m+M)g)/(m+M) amax=k((m+M)g)/k)-(m+M)g)/(m+M) amax=0/(m+M) obviously i screwed something up also why wouldn't the max acceleration of the blocks in order to remain together just be the acceleration due to gravity? Wouldn't the blocks have to be...

would it be that at the point where amax without disattachment occurs Fg=Fs so mg/k=x

max acceleration = amplitude times angular frequency squared amplitude would be the max distance from the equilibrium point for the max acceleration right?