Recent content by Rafiul Nakib
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How Can Logarithmic Differentiation Prove dy/dx Equals y/x?
x^a.y^b=(x+y)^(a+b) => ln(x^a.y^b) = ln((x+y)^(a+b)) =>a lnx + b lny = (a+b)ln(x+y) =>a. d/dx lnx + b. d/dx lny = (a+b). d/dx ln(x+y) => a/x + b/y. dy/dx = (a+b)/(x+y). dy/dx The last line is where I think I made a mistake. Can you please help?- Rafiul Nakib
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- Forum: Calculus and Beyond Homework Help
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How Can Logarithmic Differentiation Prove dy/dx Equals y/x?
the variables x and y are positive and related by x^a.y^b=(x+y)^(a+b) where a and b are positive constants. By taking logarithms of both sides, show that dy/dx=y/x. provided that bx not equal to ay.- Rafiul Nakib
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- Differentiation Logarithms
- Replies: 4
- Forum: Calculus and Beyond Homework Help