Yes they do, so instead of -10 it would be -6. Combining the resistance and capacitance would lessen the unknowns by one, so R=2 and I is our unknown
So:
-6 = I
which would make V=IR=(-6)2=-12, my assumed direction of I was wrong, so V=12, am I on the right track?
I feel like I did something...
So I can find an equivalent resistance of the two, which would equal 2, and the net current source would be 10A.
I figured since the unknown current is a factor, simplifying the circuit would combine the two, is this incorrect?
So would I use
-2-8 -I1+I2=0
instead?
Homework Statement
Find V, I1, I2 and the power of the 6Ω resistor:
Known:
R1=6Ω
R2=3Ω
Iknown1=8
Iknown2=2
RTotal=2Ω
Homework Equations
P=V2/R
P=IV
V=IR
The Attempt at a Solution
To be honest, I've been staring at the problem for hours not knowing where to begin. I thought I'd start with a...