Recent content by RainbowTuba

Yes they do, so instead of -10 it would be -6. Combining the resistance and capacitance would lessen the unknowns by one, so R=2 and I is our unknown So: -6 = I which would make V=IR=(-6)2=-12, my assumed direction of I was wrong, so V=12, am I on the right track? I feel like I did something...

So I can find an equivalent resistance of the two, which would equal 2, and the net current source would be 10A. I figured since the unknown current is a factor, simplifying the circuit would combine the two, is this incorrect? So would I use -2-8 -I1+I2=0 instead?

Homework Statement Find V, I1, I2 and the power of the 6Ω resistor: Known: R1=6Ω R2=3Ω Iknown1=8 Iknown2=2 RTotal=2Ω Homework Equations P=V2/R P=IV V=IR The Attempt at a Solution To be honest, I've been staring at the problem for hours not knowing where to begin. I thought I'd start with a...