Recent content by RalphM

I was thinking of it as being the same thing as your example of using muscle power to support a steel bar with your hand in which you concluded that the expended energy will end up as internal energy ("heat"). Wouldn't there be some sort of compression of the book and table which causing...

Hey Robert I'm no authority or anything close to that in physics but I guess what they are trying to say is that there is still energy being expended but in the form of heat rather than work. Not sure if that is correct... That leads me to another question though: if you have a stationary...

Ok I see where I'm wrong here: Drag would be larger on the heavier object at any given moment because it will always be moving faster. With regards to I guess I could re-phrase the question to: Would the heavier object have a higher acceleration at all times until both objects reach...

Why is that last part incorrect? The drag will be larger on the heavier object because it will be moving faster but I was talking about the drag relative to the mass of the object...

Hi guys, quick and simple question! If you allow 2 objects with different weights but exact same shape to free-fall in the presence of air resistance will they hit the ground at the same time (assuming terminal velocity isn't reached by either object). I'm pretty sure the heavier object hits...

in your reply to the first paragraph you mention "circuit protectors" and in the second you mention circuit "over-current protection". Is this the same thing? Thanks for the replies you've helped a lot.

About the electrical supply: Since the hot and neutral wires have a resistance and that resistance is the minimum that a circuit can have assuming you connect them with a wire having 0 Ohm. Does that mean that the maximum power that can be extracted from an outlet is constant and can be...

Thanks guys you've cleared up a lot. I feel I'm starting to get a deeper understanding. I'm still a bit unclear about power consumption. For example: Let's say you connect the hot and neutral of your 120VAC socket with a 1 Ohm wire. Then I = 120 Amps from I=V/R. Power = 14400 Watts from...

Thank you for the responses! I'm still not clear on a few things: For example: Let's say a manufacturer creates a device and minimizes the resistance of it as much as possible to minimize power losses. Since the resistance of this device is constant and the voltage from the socket is also...

Hello, I am new here and this looks like a good place to get answers! Wondering if someone could clarify something for me. When withdrawing current from a socket to an electrical device, the current is determined by I= V/R. So the manufacturer of the device can add resistors to manipulate the...