Recent content by randybrent

i give up thank you for your time

a= [.15*14sin36*9.8*2.5] /2.5 ?

Ff= .15*2.5kg*9.8= 3.675n ?

i don't know enough i guess

w i l l uk -------------------- 14 cos 36 l l l mg 14 sin 36 does this look right?

14n cos 36 - .15 =11.17 n ? 11.17/3.5= 3.19 m/s^2 ?

Friction No Clue! A 2.5 kg block is pushed along a horizontal floor by a force of magnitude 14 N at an angle = -36° with the horizontal. The coefficient of kinetic friction between the block and the floor is 0.15. Calculate the magnitudes of (a) the frictional force on the block from the...