Recent content by rapuy

As a continuation of the above solution, is it ok if I do the postmultiplication before the vector b with C on both sides? Bx - (2A + I)Ab = (2A + I)C^{-1}b ==> [Bx - (2A + I)Ab] C = (2A + I)C^{-1}C b BCx - (2A + I)AC b = (2A + I) b

Ah , I see. Here's another try: x = B^{-1}(2A + I) (C^{-1} + A)b Bx = (2A + I)(C^{-1}+ A)b Bx = (2A + I)C^{-1}b + (2A + I)Ab Bx - (2A + I)Ab = (2A + I)C^{-1}b From here, I don't know how to get rid of C^{-1}. Is it ok to postmultiply the matrices, with C?

Homework Statement If A, B, and C are nxn matrices, with B and C nonsingular, and b is an n-vector, how would you implement the formula x = B^{-1} (2A + I) (C^{-1} + A)b without computing any matrix inverses? Homework Equations Is there any identity for (2A+I)^{-1} that is...