ok so at this point it would go like this:
square root of both sides results in:
H+r = r/0.994
rearrange equation to give:
0.994H + 0.994r = r
further rearrange to give:
0.994H = 0.0050r
divide both sides by r:
0.994H/r = 0.0050
isolate for H/r:
H/r= 0.0050/0.994 =...
So this is what I did exactally:
G*(M/(H+r))^2*m=0.99(G*(M/r^2)*m)
then I carried the 0.99 into the equation to get rid of the brackets (can you cancel terms before carrying the 0.99 through?):
G*(M/(H+r)^2)*m=(0.99G)(0.99M/r^2)(0.99m)
then I canceled terms that I saw on both sides...
well when I try and solve it from the two equations pretty much everything cancels out and I'm left with H=1.01. Is this right? because the answer in the back of the book it H/R=0.005
wouldn't the 1% loss in true weight mean that W=mg at a distance H from the planet would be 1% less than W=mg at the planets surface due to a decrease in g at a distance H from the surface? I set up my equations as follows
G*(M(of planet)/(r + H) (squared))*M(of probe) = 0.99(G*(M(of...
1. Homework Statement [/b]
At a distance H abouve the suface of a planet, the true weight of a remote probe is one percent less than its true wieght on the surface. The radius of the planet is R. Find the ration H/R.
2. Homework Equations [/b]
W=mg=G*(M(of planet)/r(squared))*M(of probe)...