Recent content by rascal323

ok so at this point it would go like this: square root of both sides results in: H+r = r/0.994 rearrange equation to give: 0.994H + 0.994r = r further rearrange to give: 0.994H = 0.0050r divide both sides by r: 0.994H/r = 0.0050 isolate for H/r: H/r= 0.0050/0.994 =...

So this is what I did exactally: G*(M/(H+r))^2*m=0.99(G*(M/r^2)*m) then I carried the 0.99 into the equation to get rid of the brackets (can you cancel terms before carrying the 0.99 through?): G*(M/(H+r)^2)*m=(0.99G)(0.99M/r^2)(0.99m) then I canceled terms that I saw on both sides...

well when I try and solve it from the two equations pretty much everything cancels out and I'm left with H=1.01. Is this right? because the answer in the back of the book it H/R=0.005

wouldn't the 1% loss in true weight mean that W=mg at a distance H from the planet would be 1% less than W=mg at the planets surface due to a decrease in g at a distance H from the surface? I set up my equations as follows G*(M(of planet)/(r + H) (squared))*M(of probe) = 0.99(G*(M(of...

1. Homework Statement [/b] At a distance H abouve the suface of a planet, the true weight of a remote probe is one percent less than its true wieght on the surface. The radius of the planet is R. Find the ration H/R. 2. Homework Equations [/b] W=mg=G*(M(of planet)/r(squared))*M(of probe)...